NTA Abhyas JEE Main2020MathematicsBinomial TheoremPractice
The value of ∑ r = 1 n - 1 r + 1 C r n r + 1 is equal to
Options
- A- 1 n + 1
- B- 1 n
- C1 n + 1
- Dn n + 1
Correct answer
D. n n + 1
Step-by-step solution
∑ r = 1 n - 1 r + 1 C r n r + 1 Using C n + 1 r + 1 = n + 1 r + 1 C n r , we get, ∑ r = 1 n - 1 r + 1 1 n + 1 C r + 1 n + 1 = 1 n + 1 ∑ r = 1 n - 1 r + 1 C r + 1 n + 1 = 1 n + 1 0 - C n + 1 0 - C n + 1 1 = 1 n + 1 0 - 1 + n + 1 = n n + 1