AP EAMCET201824 Apr 2018Evening ShiftMathematicsHyperbolaActual
The locus of the point of intersection of the tangents drawn at the extremities of a normal chord of the hyperbola x^2 a^2 - y^2 b^2 =1 is
Options
- Aa^2 x^2 - b^2 y^2 =a^2+b^2
- Ba^4 x^2 - b^4 y^2 = (a^2-b^2 )^2
- Ca^3 x^2 - b^3 y^2 = (a^2+b^2 )^2
- Da^6 x^2 - b^6 y^2 = (a^2+b^2 )^2
Correct answer
D. a^6 x^2 - b^6 y^2 = (a^2+b^2 )^2
Step-by-step solution
No solution. Refer to answer key.