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AP EAMCET201822 Apr 2018Morning ShiftMathematicsHyperbolaActual

The equation of the hyperbola whose asymptotes are the lines 3 x+4 y-2=0 , 2 x+y+1=0 and which passes through the point (1,1) is

Options

  1. A6 x^2+11 x y+4 y^2-30 x+2 y+7=0
  2. B6 x^2+11 x y+4 y^2-x+2 y-22=0
  3. C6 x^2+11 x y+4 y^2-x+2 y+22=0
  4. D6 x^2+11 x y+4 y^2-3 x-7 y-11=0

Correct answer

B. 6 x^2+11 x y+4 y^2-x+2 y-22=0

Step-by-step solution

Equation to the asymptotes are given as aligned 3 x+4 y-2 & =0 2 x+y+1 & =0 aligned and Eqs.(i) and (ii) may be given by (3 x+4 y-2)(2 x+y+1)=0 As, the equation to the hyperbola will differ from Eq. (iii) only by a constant, it may be given by (3 x+4 y-2(2 x+y+1)= (where is a constant) (1,1) lies on the curve given by Eq. (iv), we have aligned & & (3+4-2)(2+1+1) & = & & (5)(4)= & =20 aligned Hence, the equation of the hyperbola will be aligned & (3 x+4 y-2)(2 x+y+1)=20 & 6 x^2+3 x y+3 x+8 x y+4 y^2 & +4 y-4 x-2 y-2

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