NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
The general solution of the differential equation 2 x - y + 1 d x + 2 y - x + 1 d y = 0 is
Options
- Ax 2 + y 2 + x y - x + y = c
- Bx 2 + y 2 - x y + x + y = c
- Cx 2 - y 2 + 2 x y - x + y = c
- Dx 2 - y 2 - 2 x y + x - y = c
Correct answer
B. x 2 + y 2 - x y + x + y = c
Step-by-step solution
xdy - 2 ydy - dy = 2 xdx - ydx + dx xdy + ydx - 2 ydy - dy - 2 xdx - dx = 0 d(xy) - 2 ydy - dy - 2 xdx - dx = 0 on integrating, we get, xy - y 2 - y - x 2 - x = c