NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
The curve satisfying the differential equation d x d y = x + 2 y x 2 y - 2 x 3 and passing through ( 1 ,   0 ) is given by
Options
- Ax 2 + y 2 = 1
- Bx 2 + y 2 + y x = 1
- Cy 2 - y x - x 2 = - 1
- Dx 2 - y 2 = 1
Correct answer
B. x 2 + y 2 + y x = 1
Step-by-step solution
Given equation is 2 x d x + 2 y d y + d y x = 0 Integrating, we get, x 2 + y 2 + y x = c As ( 1 ,   0 ) lies on it, hence, c = 1