NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
The solution of the differential equation x d y + y x d x = d x x is (where, c is an arbitrary constant)
Options
- Ay = 1 + c e 1 / x
- By = c e 1 / x
- Cy = c e 1 / x - 1
- Dx y = 1 - c e 1 / x
Correct answer
A. y = 1 + c e 1 / x
Step-by-step solution
The given differential equation can be written as, d y d x + 1 x 2 ⋅ y = 1 x 2 Integrating factor is e - 1 / x ⇒ y . e - 1 / x = ∫ 1 x 2 . e - 1 / x   d x Hence, the solution is y = 1 + c e 1 / x