NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
Let y = f x be the solution of the differential equation d y d x = - 2 x y - 1 with f 0 = 1 , then l i m x → ∞ f x is equal to
Options
- A1 2
- B0
- Ce
- D1
Correct answer
D. 1
Step-by-step solution
d y d x = - 2 x y - 1 d y d x + 2 x y = 2 x Ι . F . = e ∫ 2 x d x = e x 2 y ⋅ e x 2 = ∫ e x 2 2 x d x y ⋅ e x 2 = e x 2 + C ∵ y 0 = 1 ⇒ 1 = 1 + C ⇒ C = 0 Hence, the solution is y e x 2 = e x 2 ⇒ y = 1 = f x l i m x → ∞ f x = 1