NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
Let the curve y = f x satisfies the equation d y d x = 1 - 1 x 2 and passes through the point 2 , 7 2 , then the value of f 1 is
Options
- A3
- B2
- C7 2
- D1
Correct answer
A. 3
Step-by-step solution
d y d x = 1 - 1 x 2 So, y = x + 1 x + C Since, it passes through 2 , 7 2 7 2 = 2 + 1 2 + C ⇒ C = 1 y = x + 1 x + 1 = f x f 1 = 3