NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
If the solution of the differential equation x 2 d y + 2 x y d x = sin ⁡ x d x is x k y + cos ⁡ x = C (where C is an arbitrary constant), then the value of k is equal to
Correct answer
2
Step-by-step solution
The given equation is d x 2 y = sin ⁡ x d x On integrating, we get, x 2 y = - cos ⁡ x + C or x 2 y + cos ⁡ x = C ⇒ k = 2