NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
If a and b are arbitrary constants, then the order and degree of the differential equation of the family of curves a x 2 + b y 2 = 2 respectively are
Options
- A2,2
- B1,2
- C1,1
- D2,1
Correct answer
D. 2,1
Step-by-step solution
a x 2 + b y 2 = 1 On differentiating w.r.t. x a x + b y d y d x = 0 ... 1 Again differentiating w.r.t. x a + b y d 2 y d x 2 + b d y d x 2 = 0 ... 2 From 1 & 2 , we get, x - b y d 2 y d x 2 - b d y d x 2 + b y d y d x = 0 - x y d 2 y d x 2 - x d y d x 2 + y d y d x = 0 Hence, order = 2 , degree = 1