NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
The solution of the differential equation d y d x = x y + y x y + x is y - λ x = ln ⁡ x y + C (where, C is an arbitrary constant and x , y > 0 ). Then, the value of λ is equal to
Options
- A1
- B1 2
- C2
- D4
Correct answer
A. 1
Step-by-step solution
The given equation is 1 + 1 y d y = 1 + 1 x d x On integrating, we get, y + ln ⁡ y = x + ln ⁡ x + C or y - x = ln ⁡ x y + C ∴ λ = 1 .