NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
The solution of the differential equation x d y d x = y ln ⁡ y 2 x 2 is (where, c is an arbitrary constant)
Options
- Ay = x . e c x + 1
- By = x . e c x - 1
- Cy = x 2 . e c x + 1
- Dy = x . e c x 2 + 1 2
Correct answer
D. y = x . e c x 2 + 1 2
Step-by-step solution
Putting y = x v   and   d y d x = v + x d v d x So, v + x d v d x = 2 v ln ⁡ v ⇒   ∫ d x x = ∫ d v v ( 2 ln ⁡ v - 1 ) On integrating, we get,   y = x ⋅ e c x 2 +   1 2