NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
The order of the differential equation of the family of curves y = k 1 2 k 2 x + k 3 3 x + k 4 is (where, k 1 , k 2 , k 3 , k 4 are arbitrary constants)
Options
- A4
- B5
- C3
- D6
Correct answer
C. 3
Step-by-step solution
The given family of curves is y = k 1 2 k 2 x + k 3 3 k 4 3 x = k 1 2 k 2 x + k 5 3 x which has ‘ 3 ’ arbitrary constants. Hence, the order will be ‘ t h r e e ’