NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
If the solution of the differential equation 1 + e x y d x + e x y 1 - x y d y = 0 is x + k y e x y = C (where, C is an arbitrary constant), then the value of k is equal to
Correct answer
1
Step-by-step solution
The given equation is e x y d x - x y d y + e x y d y + d x = 0 or e x y y d x y + e x y d y + d x = 0 ⇒ d e x y y + d x = 0 On integrating, we get, e x y y + x = C ⇒ k = 1