NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
The differential equation of the curve for which the point of tangency (closer to the x -axis) divides the segment of the tangent between the coordinate axes in the ratio 1 : 2 , is
Options
- Ax d y = 2 y d x
- Bx d y = y d x
- Cx d y + 2 y d x = 0
- Dx d y + y d x = 0
Correct answer
C. x d y + 2 y d x = 0
Step-by-step solution
Equation of the tangent is Y - y = m X - x ⇒ A ≡ x - y m , 0 , B ≡ 0 , y - m x Using section formula, we get, y = 1 ⋅ y - m x + 2 0 1 + 2 or 3 y = y - m x ⇒ m = d y d x = - 2 y x i.e. x d y + 2 y d x = 0