NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice
The solution of the differential equation d y d x = 2 x - y x - 6 y is (where c is an arbitrary constant)
Options
- A4 x y = x 2 - 3 y + c
- Bx y = x 2 - y 2 + c
- Cx y = x 2 + 3 y 2 + c
- Dx y = x 2 + c
Correct answer
C. x y = x 2 + 3 y 2 + c
Step-by-step solution
Given equation is x d y - 6 y d y = 2 x d x - y d x ⇒ x d y + y d x = 2 x d x + 6 y d y or d x y = 2 x d x + 6 y d y On integrating, we get, x y = x 2 + 3 y 2 + c