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NTA Abhyas JEE Main2020MathematicsDifferential EquationsPractice

The straight line y = 2 x meets y = f x at P , where f x is a solution of the differential equation d y d x = x 2 + x y x 2 + y 2 such that f 1 = 3 , then f ′ x at point P is

Options

  1. A3 5
  2. B5 3
  3. C2
  4. D1

Correct answer

A. 3 5

Step-by-step solution

Note f ′ x = d y d x = 1 + y x 1 + y x 2 At point P , y x = 2 So, d y d x P = 1 + 2 1 + 4 = 3 5

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