AP EAMCET202422 May 2024Evening ShiftMathematicsIndefinite IntegrationActual
If (6 ^2 x+17 x+12 )^ x d x=f(x)+c then, f ( 2 )=
Options
- A1 6 [ 5^5+ 7^7-12 ]
- B1 6 [7 5+5 7+29]
- C1 6 [14 5+15 7+12]
- D1 6 [15 5+14 7-29]
Correct answer
D. 1 6 [15 5+14 7-29]
Step-by-step solution
I = (6 ^2 x+17 x+12 )^ x d x Let x=t x d x=d t aligned & I = (6 t^2+17 t+12 ) d t & I =t (6 t^2+17 t+12 )- t(12 t+17) 6 t^2+17 t+12 d t & I =t (6 t^2+17 t+12 )- 2 d t+ 17 t+24 6 t^2+17 t+12 d t & I =t (6 t^2+17 t+12 )-2 t+ 17 12 12 t+17 6 t^2+17 t+12 d t & - 1 12 1 6 t^2+17 t+12 d t & I =t (6 t^2+17 t+12 )-2 t+ 17 12 (6 t^2+17 t+12 ) & - 1 4 d t 3 t+4 + 1 6 d t 2 t+3 aligned aligned & I =t (6 t^2+17 t+12 )-2 t+ 17 12 (6 t^2+17 t+12 ) & - (3 t+4) 12 + (2 t+3) 12 + C & I = [ array c (12 x+17) ((2 x+3)(3 x+4)] - (3 x+