NTA Abhyas JEE Main2020MathematicsPermutation and CombinationPractice
The sum of the divisors of 9600 is
Options
- A3048
- B6120
- C31620
- D24384
Correct answer
C. 31620
Step-by-step solution
9600 = 96 × 100 = 2 7 × 3 1 × 5 2 Number of divisors = 8 × 2 × 3 = 48 Sum of divisors = 2 0 + 2 1 + 2 2 + . . . . . . . + 2 7 3 0 + 3 1 5 0 + 5 1 + 5 2 = 2 8 - 1 2 - 1 × 3 2 - 1 3 - 1 × 5 3 - 1 5 - 1 = 255 × 8 2 × 124 4 = 31620