The number of ways in which we can put 5 different balls in 5 different boxes such that atmost three boxes are empty, is equal to

Step-by-step solution

5 different balls can be put in 5 different boxes in 5 5 ways. At most 3 empty boxes are allowed Number of ways in which 4 boxes are empty = 5 C 1 × 1 5 = 5 . Number of ways in which 5 boxes are empty = 0 , as balls has to be placed in one of the boxes. ⇒ Required number of ways = 5 5 - 5 .