NTA Abhyas JEE Main2020MathematicsPermutation and CombinationPractice
Out of 10 white, 8 black and 6 red balls, the number of ways in which one or more balls can be selected is (assuming balls of the same colour are identical)
Options
- A681
- B691
- C679
- D692
Correct answer
D. 692
Step-by-step solution
Required number of ways = 10 + 1 8 + 1 6 + 1 - 1 = 11 × 9 × 7 - 1 = 693 - 1 = 69 2