Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020MathematicsPermutation and CombinationPractice

Out of 10 white, 8 black and 6 red balls, the number of ways in which one or more balls can be selected is (assuming balls of the same colour are identical)

Options

  1. A681
  2. B691
  3. C679
  4. D692

Correct answer

D. 692

Step-by-step solution

Required number of ways = 10 + 1 8 + 1 6 + 1 - 1 = 11 × 9 × 7 - 1 = 693 - 1 = 69 2

Practice Permutation and Combination on Quantrex Academy →

More from Permutation and Combination

All Permutation and Combination questions Full Permutation and Combination list All NTA Abhyas JEE Main PYQs