If m number of integers greater than 7000 can be formed with the digits 3,5 , 7,8 and 9 , such that no digit is being repeated, then the value of m 100 is

Step-by-step solution

A five digit integer is always greater than 7000 . The number of such integers are 5 P 5 = 5 ! = 120 . For a four digit integer to be greater than 7000 , it must begin with 7,8 or 9 . The number of such integers are 3 4 P 3 = 72 . Hence, the required number of such integers are 120 + 72 = 192 . ⇒ m = 19 2 ⇒ m 100 = 1.92 .