The number of numbers, lying between 99 and 1000 that can be made from the digits 2 , 3 , 7 , 0 , 8 and 6 when the digits occur only once in each number, is

Step-by-step solution

Required number of numbers = 6 P 3 − 5 ​ P 2 = 120 − 20 = 100 . Since, between 99   &   1000 , the numbers are of 3 digits, but those numbers should be omitted in which 0 comes at hundreds place .