Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020MathematicsPermutation and CombinationPractice

A word has 4 identical letters and rest all are distinct letters. If the total number of words that can be made with the letters of the word be 210, then the total number of different letters in the word is equal to

Options

  1. A3
  2. B5
  3. C4
  4. D7

Correct answer

C. 4

Step-by-step solution

Let the number of distinct letters other than the identical letters be n . Total letters = n + 4 Identical = 4 , Distinct = n Number of ways in which they can be arranged = n + 4 ! 4 ! ⇒ n + 4 ! 4 ! = 210 ⇒ n + 4 n + 3 n + 2 … 6.5 = 210 = 7 × 6 × 5 ⇒ n + 4 = 7 ⇒ n = 3 So, the required number of total different letters = 3 + 1 = 4

Practice Permutation and Combination on Quantrex Academy →

More from Permutation and Combination

All Permutation and Combination questions Full Permutation and Combination list All NTA Abhyas JEE Main PYQs