NTA Abhyas JEE Main2020MathematicsPermutation and CombinationPractice
The position vector of the point P is π → = x i ^ + y j ^ + z k ^ , where x , y , z ∈ N. If a → = i ^ + j ^ + k ^ and π → . a → = 10 , then the number of possible positions of point P is equal to
Options
- A36
- B72
- C66
- D54
Correct answer
A. 36
Step-by-step solution
π → . a → = 10 ⇒ x + y + z = 10 The required number of positions = The number of positive integral solutions of x + y + z = 10 = C 3 - 1 10 - 1 = 9 × 8 2 = 36