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NTA Abhyas JEE Main2020MathematicsPermutation and CombinationPractice

A student has to answer 10 out of 13 questions in an examination. The number of ways in which he can answer, if he must answer atleast three of the first five questions, is

Options

  1. A276
  2. B600
  3. C840
  4. D640

Correct answer

A. 276

Step-by-step solution

The possible cases are: Required number of ways = C 5 3 × C 8 7 + C 5 4 × C 8 6 + C 5 5 × C 8 5 = 5 × 4 2 × 8 + 5 × 8 × 7 2 + 1 × 8 × 7 × 6 3 × 2 = 80 + 140 + 56 = 276

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