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Bag A contains 4 green and 3 red balls and bag B contains 4 red and 3 green balls. One bag is taken at random and a ball is drawn and noted to be green. The probability that it comes from bag B , is

Options

  1. A2 7
  2. B2 3
  3. C3 7
  4. D1 3

Correct answer

C. 3 7

Step-by-step solution

Let A is the event that ball is drawn from Bag A , B is the event that ball is drawn from Bag B and G be the event that a green ball is drawn ⇒ P G A =   4 C 1   7 C 1 = 4 7   a n d   P G B =   3 C 1   7 C 1 = 3 7 Now, P B G = P ( B ) . P G B P ( A ) P G A + P ( B ) P G B P B G = 1 2 . 3 7 1 2 . 4 7 + 1 2 . 3 7 = 3 7

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