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A box contains 9 slips bearing numbers - 3 , - 2 , - 1, 0 , 1, 2 , 3, 4 and 5 . An experiment consists of drawing a slip from this box and replacing it back in the box after noting the number. This experiment is repeated 9 times. These 9 numbers are now chosen as elements of a 3 × 3 matrix, then the probability that the matrix is skew symmetric is

Options

  1. A1 9 6
  2. B343 9 9
  3. C1 9 9
  4. D1 9 7

Correct answer

B. 343 9 9

Step-by-step solution

Total cases = 9 9 All diagonal elements are zero and a i j = - a j i So favourable cases = 7 3 Hence, required probability = 7 3 9 9

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