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5 different games are to be distributed among 4 children randomly. The probability that each child gets atleast one game is

Options

  1. A1 4
  2. B15 64
  3. C21 64
  4. D17 632

Correct answer

B. 15 64

Step-by-step solution

Total cases = 4 5 = 1024 Favourable cases = 5 ! 1 ! 3 2 ! × 1 3 ! × 4 ! (By grouping) = 24 0 Hence, required probability = 240 1024 = 15 64

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