NTA Abhyas JEE Main2020MathematicsProbabilityPractice
If 2 distinct numbers are between 0 to 180 (both inclusive) and the probability that their average is 60 is k , then 1086 k is equal to
Correct answer
4
Step-by-step solution
Let 2 distinct number are a , b a + b 2 = 60 ⇒ a + b = 120 if a = 0 then b = 120 a = 1 then b = 119 . . . a = 59 then b = 61 favourable case = 60 Total case = 181 C 2 Required probability = 60 181 C 2 = 2 543 = k 1086 k = 4