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A subset of 5 elements is chosen from the set of first 15 natural numbers. The probability that at least two of the five numbers are consecutive is λ , then the value of 22 λ is equal to

Correct answer

26

Step-by-step solution

Total cases = 15 C 5 Unfavourable cases (no two are consecutive) = 11 C 5 Required probability = 1 - 11 C 5 15 C 5 = 1 - 2 13 = 11 13

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