The mean and variance of a random variable X having a binomial probability distribution are 6 and 3 respectively, then the probability P X ≥ 2 is

Step-by-step solution

n p = 6 ,   n p q = 3 q = 1 2 ,   p = 1 2 ,   n = 1 2 P X ≥ 2 = 1 - P X = 0 - P X = 1 = 1 - 12 C 0 1 2 0 1 2 12 - 12 C 1 1 2 1 1 2 11 = 1 - 13 2 12 = 4083 4096