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Each of A and B tosses a fair coin simultaneously 10 times. The probability that both of them will not get tail at the same toss is equal to

Options

  1. A3 4 10
  2. B2 7 10
  3. C1 4 10
  4. D1 2 10

Correct answer

A. 3 4 10

Step-by-step solution

For any toss, total cases: H H , H T , T H , T T ( 4 cases) ∴ both of them will not get tail at same toss, then the favorable cases: H H , H T , T H ( 3 cases) Hence, the required probability = 3 4 10

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