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NTA Abhyas JEE Main2020MathematicsQuadratic EquationPractice

If α ,   β are the roots of the equation x 2   – 3 x + 4 = 0 , then the equation whose roots are α - 2 α + 2 ,   β - 2 β + 2 is

Options

  1. A7 x 2 – 1 = 0
  2. B7 x 2 + 1 = 0
  3. C7 x 2 + 2 = 0
  4. D7 x 2 – 2 = 0

Correct answer

B. 7 x 2 + 1 = 0

Step-by-step solution

Replace x by 2 1 + x 1 - x 4 1 + x 1 - x 2 - 3 2 1 + x 1 - x + 4 = 0 ⇒ 7 x 2 + 1 = 0

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