NTA Abhyas JEE Main2020MathematicsQuadratic EquationPractice
The possible values of n for which the equation n x 2 + 2 n – 1 x + n – 1 = 0 has roots of opposite sign is/are given by
Options
- Ano values of n
- Ball values of n
- C– 1 < n < 0
- D0 < n < 1
Correct answer
D. 0 < n < 1
Step-by-step solution
D = 2 n – 1 2 – 4 n n – 1 = 4 n 2 + 1 – 4 n – 4 n 2 + 4 n = 1 > 0 Product of roots = n - 1 n < 0 ⇒ n n – 1 < 0 ⇒ n ∈ 0 , 1