NTA Abhyas JEE Main2020MathematicsQuadratic EquationPractice
If α and β are the roots of the equation 8 x 2 - 3 x + 27 = 0 , then the value of α 2 β 1 3 + β 2 α 1 3 is
Options
- A1 3
- B1 4
- C1 5
- D1 6
Correct answer
B. 1 4
Step-by-step solution
α + β = 3 8 , α β = 27 8 α 2 β 1 3 + β 2 α 1 3 = α 3 1 3 + β 3 1 3 α β 1 3 α + β α β 1 3 = 3 8 27 8 1 3 = 3 8 3 2 = 1 4