NTA Abhyas JEE Main2020MathematicsQuadratic EquationPractice
If f x = a x 2 + b x + c , f - 1 > 1 2 , f 1 < - 1 and f - 3 < - 1 2 , then
Options
- Aa = 0
- Ba < 0
- Ca > 0
- DSign of a can not be determined
Correct answer
B. a < 0
Step-by-step solution
Clearly, parabola is opening downwards ⇒ a < 0 .