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If p , q , r , s ∈ R, then the equation x 2 + p x + 3 q - x 2 + r x + q - x 2 + s x - 2 q = 0 has

Options

  1. A6 real roots
  2. Bat least two real roots
  3. C2 real and 4 imaginary roots
  4. D4 real and 2 imaginary roots

Correct answer

B. at least two real roots

Step-by-step solution

For real roots, p 2 - 12 q ≥ 0 ...(i) r 2 + 4 q ≥ 0 ...(ii) s 2 - 8 q ≥ 0 ...(iii) If q > 0 , then (ii) is always true. If q < 0 , then (i) and (iii) are always true. So, the equation has atleast two real roots.

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