NTA Abhyas JEE Main2020MathematicsQuadratic EquationPractice

If the equation x 2 + a x + b = 0 has distinct real roots and x 2 + a x + b = 0 has only one real root, then

Options

Ab = 0 , a > 0
Bb > 0 , a < 0
Cb > 0 , a > 0
Db < 0 , a > 0

Correct answer

A. b = 0 , a > 0

Step-by-step solution

Since the equation x 2 + a x + b = 0 has distinct real roots and x 2 + a x + b = 0 has only one real root So, one root of the equation x 2 + a x + b = 0 will be zero and the other root will be negative. Hence, b = 0 and a > 0

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