NTA Abhyas JEE Main2020MathematicsQuadratic EquationPractice
The product of the roots of the equation whose roots are greater by unity than the roots of the equation x 3 - 5 x 2 + 6 x - 3 = 0 is equal to
Options
- A3
- B12
- C15
- D18
Correct answer
C. 15
Step-by-step solution
Let the roots of the equation x 3 - 5 x 2 + 6 x - 3 = 0 are α ,   β ,   γ , then α + β +   γ = 5 ,   α β + β γ + γ α = 6 ,   α β γ = 3 Roots of the other equation are greater by unity, so it will be α + 1 ,   β + 1 ,   γ + 1 Now, α + 1 β + 1 γ + 1 = α β γ + α β + β γ + γ α + α + β + γ + 1 = 3 + 6 + 5 + 1 = 15