NTA Abhyas JEE Main2020MathematicsQuadratic EquationPractice
If α is a root of the equation 4 x 2 + 2 x - 1 = 0 and f x = 4 x 3 - 3 x + 1, then 2 f α + α is equal to
Options
- A- 1
- B0
- C1
- D2
Correct answer
C. 1
Step-by-step solution
4 α 2 + 2 α - 1 = 0 2 f α + α = 2 4 α 3 - 3 α + 1 + α = 2 α 4 α 2 + 1 - 2 α = 2 α 1 - 2 α + 1 - 2 α = 2 α - 2 α 2 + 1 - 2 α = 2 - 2 α 2 - α + 1 = - 4 α 2 - 2 α + 2 = - 1 + 2 = 1