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AP EAMCET202317 May 2023Evening ShiftMathematicsIndefinite IntegrationActual

g(x) is an anti derivative of f(x)=1+2^x 2 and the graph of y=g(x) passes through (-1, 1 2 ) . Then the curve meets the Y - axis at

Options

  1. A(0,1)
  2. B(0,2)
  3. C(0,-2)
  4. D(1,1)

Correct answer

B. (0,2)

Step-by-step solution

f(x)=1+2^x 2 aligned & f(x)= (1+2^x 2 ) d x & g(x)=x+ 2^x 2 2 +c aligned g (x)=x+2^x+c y=x+2^x+c ...(i) Equation (i) passes through (-1, 1 2 ) 1 2 =-1+2⁻¹+c c=1 Putting value of c in eq ^ n (i), we get y=x+2^x+1 ...(ii) When curve (ii) meets y -axis: x=0 y=0+2^ +1=2 Curve meet y -axis at the point (0,2)

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