NTA Abhyas JEE Main2020MathematicsStatisticsPractice

Let V 1 = variance of 13,16,19 . . . . . . . . . . 103 and V 2 = variance of 20,26,32 . . . . . . . . . . 200 . Then V 1 : V 2 is

Options

A1 : 2
B1 : 1
C4 : 9
D1 : 4

Correct answer

D. 1 : 4

Step-by-step solution

V 1 = variance of 13,16,19 . . . . . . . . . . 103 = variance of 3,6 , 9 . . . . . . . . . . 93 = 9 of variance of 1,2 , 3 . . . . . . . . . . 31 V 2 = variance of 20,26,32 . . . . . . . . . . 200 = variance of 6,12,18 . . . . . . . . . . 186 = 36 of variance of 1,2 , 3 . . . . . . . . . . 31 V 1 V 2 = 1 4

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