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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Statistics

NTA Abhyas 2020 · Mathematics · Statistics

If 2 data sets having 10 and 20 observations have coefficients of...

If 22 data sets having 1010 and 2020 observations have coefficients of variation 5050 and 6060 respectively and arithmetic means 3030 and 2525 respectively, then the combined variance of those 3030 observations is

Options

  1. A20753\dfrac{2075}{3}
  2. B20759\dfrac{2075}{9}
  3. C10009\dfrac{1000}{9}
  4. D10753\dfrac{1075}{3}

Correct answer

B. 20759\dfrac{2075}{9}

Step-by-step solution

Given,

n1=10,x¯1=30,CV1=50{n}_{1} = 10, \overset{¯}{x}1 = 30, C{V}_{1} = 50
n2=20,x¯1=25,CV2=60{n}_{2} = 20, \overset{¯}{x}1 = 25, C{V}_{2} = 60
CV1=σ1x¯1×100⇒50=σ130×100⇒σ1=15C{V}_{1} = \dfrac{{\sigma}_{1}}{{\overset{¯}{x}}_{1}} \times 100 ⇒ 50 = \dfrac{{\sigma}_{1}}{30} \times 100 ⇒ {\sigma}_{1} = 15
CV2=σ2x¯2×100⇒60=σ125×100⇒σ2=15C{V}_{2} = \dfrac{{\sigma}_{2}}{{\overset{¯}{x}}_{2}} \times 100 ⇒ 60 = \dfrac{{\sigma}_{1}}{25} \times 100 ⇒ {\sigma}_{2} = 15
Combined mean =10×30+20×2530=803= \dfrac{10 \times 30 + 20 \times 25}{30} = \dfrac{80}{3}
d1=x¯1−x¯=103,d2=x¯−x¯2=53{d}_{1} = \overset{¯}{x}1 - \overset{¯}{x} = \dfrac{10}{3}, {d}_{2} = \overset{¯}{x} - \overset{¯}{x}2 = \dfrac{5}{3}
Combined variance =n1σ12+n2σ22+n1d12+n2d22n1+n2= \dfrac{{n}_{1}{σ}_{1}^{2} + {n}_{2}{σ}_{2}^{2} + {n}_{1}{d}_{1}^{2} + {n}_{2}{d}_{2}^{2}}{{n}_{1} + {n}_{2}}
=2250+4500+10009+500930= \dfrac{2250 + 4500 + \dfrac{1000}{9} + \dfrac{500}{9}}{30}
=622527=20759= \dfrac{6225}{27} = \dfrac{2075}{9}

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