NTA Abhyas JEE Main2020MathematicsStatisticsPractice
The mean deviation of the series a 2   ,   a 2 + d   ,   a 2 + 2 d ,   . . . . . ,   a 2 + 2 n d from its median is
Options
- An + 1 d 2 n + 1
- Bn d 2 n + 1
- Cn n + 1 d 2 n + 1
- D2 n + 1 d n n + 1
Correct answer
C. n n + 1 d 2 n + 1
Step-by-step solution
Median or mean x ¯ = 2 n + 1 2 ⋅ a 2 + a 2 + 2 n d 2 n + 1 = a 2 + n d ∵   M e a n = M e d i a n Σ x i - x ¯ = 2 d 1 + 2 + . . . . + n = n n + 1 d ∴   M . D . = n n + 1 d 2 n + 1