NTA Abhyas JEE Main2020MathematicsStatisticsPractice
Mean deviation of the series a 2 , a 2 + d , a 2 + 2 d , . . . . . . . . , a 2 + 2 n d from its mean is
Options
- An + 1 d 2 n + 1
- Bn d 2 n + 1
- Cn n + 1 d 2 n + 1
- D2 n + 1 d n n + 1
Correct answer
C. n n + 1 d 2 n + 1
Step-by-step solution
mean x ¯ = 2 n + 1 2 · a 2 + a 2 + 2 n d 2 n + 1 = a 2 + n d Σ x — x ¯ = 2 d 1 + 2 + … … + n = n n + 1 d ∴ M · D · = n n + 1 d 2 n + 1