NTA Abhyas JEE Main2020MathematicsStatisticsPractice
The mean and variance of 10 observations are found to be 10 and 5 respectively. On rechecking it is found that an observation 5 is incorrect. If the incorrect observation is replaced by 15 , then the correct variance is
Options
- A7
- B8
- C9
- D4
Correct answer
D. 4
Step-by-step solution
x ¯ o l d = 10 = Σ x i 10 ⇒ Σ x i o l d = 100 Σ x i new = 100 - 5 + 15 = 110 x ¯ new = 110 10 = 11 V a r old = 5 = Σ x i o l d 2 10 - x ¯ o l d 2 Σ x i o l d 2 = 1050 Σ x i new 2 = 1050 - 25 + 225 = 1250 Var n e w = 1250 10 - 11 2 = 125 - 121 = 4