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Let a → = i ^ + 2 j ^ + 3 k ^ , b → = 2 i ^ + 3 j ^ + k ^ , c → = k ^ + i ^ and x → × b → = a → × c → × b → . If x → ⋅ a → = 0 , then x → is equal to use 3 = 1 . 73 )

Correct answer

3.46

Step-by-step solution

x → × b → = a → ⋅ b → c → - b → ⋅ c → a → = 11 c → - 3 a → As, a → ⋅ b → = 1 1 and b → ⋅ c → = 3 Now x → × b → × a → = 11 c → × a → ⇒ x → ⋅ a → b → - b → ⋅ a → x → = 11 c → × a → ⇒ x → = a → × c →   a s   a → ⋅ x → = 0 ⇒ x &#859

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