NTA Abhyas JEE Main2020MathematicsVector AlgebraPractice
A vector r → is equally inclined with the vectors a → = cos ⁡ θ i ^ + sin ⁡ θ j ^ ,   b → = - sin ⁡ θ i ^ + cos ⁡ θ j ^ and c → = k ^ , then the angle between r → and a → is
Options
- Ac o s - 1 1 2
- Bc o s - 1 1 3
- Cc o s - 1 1 3
- Dcos - 1 1 2
Correct answer
C. c o s - 1 1 3
Step-by-step solution
a → , b → , c → are unit vectors and mutually perpendicular vectors and r → is equally inclined to all 3 vectors ⇒ r → = λ a → + b → + c → ⇒ r → = λ cos θ - sin θ i ^ + sin θ + cos θ j ^ + k ^ Angle between r → and a → is cos α = r → ⋅ a → r → a → = λ cos 2 θ - sin θ cos θ + sin 2 θ + sin θ cos θ 1 × 3 λ cos α = 1 3 ⇒ α = c o s - 1 1 3