NTA Abhyas JEE Main2020MathematicsVector AlgebraPractice
Let V → θ = cos θ + sec θ a ^ + cos θ - s e c θ b ^ , where a ^ and b ^ are unit vectors and the angle between a ^ and b ^ is 60 o , then the minimum value of V → 4 is equal to
Correct answer
12
Step-by-step solution
V → 2 = cos θ + sec θ a ^ + cos θ - sec θ b ^ 2 = cos θ + sec θ 2 + cos θ - sec θ 2 + ( cos θ - sec θ ) ( cos θ + sec θ ) = 3 cos 2 θ + sec 2 θ ≥ 2 3 ⇒ least value of V → 2 = 2 3 ⇒ least value of V → 4 = 12